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Two point charges placed at a …

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Two point charges placed at a distance R in air exert a force F on each other. At what distance will these experience the same force F in a medium of dielectric constant K?
  • 1 answers

Sia ? 4 years, 5 months ago

F (air) = (1/4 pi eo) [qQ/r2]
F(medium) = (1/4 pi eo*k) [qQ/R2

given> F(medium) = F(air) 
(1/4 pi eo*k) [qQ/R2] = (1/4 pi eo) [qQ/r2
(1/k) [1/R2] = [1/r2]
kR2 = r2 
R2 = r2/k 
R = r/ [rootk] 

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