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Two point charges placed at a …

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Two point charges placed at a distance R in air exert a force F on each other. At what distance will these experience the same force F in a medium of dielectric constant K?

Posted by Kashish Mandlecha 4 years, 8 months ago

CBSE > Class 12 > Physics

1 answers

Sia ? 4 years, 8 months ago

F (air) = (1/4 pi eo) [qQ/r²]
F(medium) = (1/4 pi eo*k) [qQ/R²]

given> F(medium) = F(air)
(1/4 pi eo*k) [qQ/R²] = (1/4 pi eo) [qQ/r²]
(1/k) [1/R²] = [1/r²]
kR² = r²
R² = r²/k
R = r/ [rootk]

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