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solve for x 36x^2-12ax+(a^2-b^2)=0

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solve for x 36x^2-12ax+(a^2-b^2)=0
  • 2 answers

Gokul J 4 years, 7 months ago

36x2−12ax+(a2−b2)=0 Ax2+Bx+C=0 from, A=36  B=−12a  C=(a2−b2) Roots of quadratic equation formula : x=2A−B±B2−4AC​​ =2×3612a±144a2−144(a2−b2)​​ =7212a±144b2​​ =7212a±12b​ =6a±b​ ⇒x=6a+b​ or 6a−b​

Amani Aggarwal 4 years, 7 months ago

pls reply
http://mycbseguide.com/examin8/

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