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Find a quadratic polynomial , the sum of whose zero is 8 and their product is 12 . Hence find the zeroes of the polynomial.

Posted by Khushi 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Khushi 4 years, 7 months ago

Thanks

0Thank You

Sarthak?? Jaiswal 4 years, 7 months ago

A(alpha)+B(beta)=8 A(alpha)×B(beta)=12 as we know, A+B=-b/a therefore, -b/a=8/1 so, b=-8,a=1 Now as we know, A×B=c/a therefore, c/a=12/1 so, c=12 Now,as we know quadratic polynomials are in the form of ax²+bx+c=0 therefore, x²-8x+12=0 x²-4x-3x+12=0 x(x-4)-3(x-4)=0 (x-4)(x-3)=0 Now, if, x-4=0 Therehore, x=4 And, if, x-3=0 Therefore, x=3.

2Thank You

Sarangi Jayakumar 4 years, 7 months ago

x2-8x+12

1Thank You

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