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Evaluate : (I) sin square 63 …

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Evaluate : (I) sin square 63 degree + sin square 27 degree / cos square 17 degree + cos square 73 degree (ii) sin 25 degree × cos 65 degree + cos 25 degree × sin 65 degree

Posted by Prachi Shukla 4 years, 7 months ago

CBSE > Class 10 > Mathematics

4 answers

Good Day 4 years, 7 months ago

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Prachi Shukla 4 years, 7 months ago

Thanks broo

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Good Day 4 years, 7 months ago

2 = Sin 25° × Cos 65° + Cos 25°× Sin 65° =Sin 25°× Sin(90°-65°) + Cos 25°× Cos(90°-65°) = Sin^2 25°+ Cos^2 25° Using identities Sin^2A + Cos^2A=1 = 1

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Good Day 4 years, 7 months ago

1 = sin ^2 63° + sin ^2 27°÷cos^2 17°+ cos ^ 73° = Sin^2 63° + cos^2(90°- 27°)÷sin^2 ( 90°-17°)+ cos^2 73° = Sin^2 63° + cos^2 63°÷ sin^2 73° + cos^2 73° Using identities Sin^2A + Cos^2A= 1 =1÷1 Ans :1

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