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Give me the solution of this question : sec A (1-sin A)(secA+tanA)
  • 2 answers

Saras Rajput 4 years, 7 months ago

1

Gunn Bhatia 4 years, 7 months ago

=sec A(1 - sin A)(sec A + tanA) = 1/ cos A(1-sinA)(1/cosA + sinA/cosA) =(1- sinA)(1 + sinA)/cosA ×cosA = 1 - sin^2 A/cos^2 A =cos^2 A/ cos^2 A [[ since, cos^2 A + sin^2 A = 1]] = 1
http://mycbseguide.com/examin8/

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