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In given fig o is centre of circle.om is perpendicular BC,ol perpendicular ab ,on perpendicular AC,Om=on=ok.is triangle ABC equilateral triangle.give reason.chapter circle grade 9

    • Posted by Shreeji Vakil 5 years ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Tanishq Pandya 5 years ago

    Given :- O is the centre of a circle. OM is perpendicular to BC. So, OM bisects BC (the perpendicular from the centre of a circle to a chord bisects the chord) ON is perpendicular to AC. So, ON bisects AC (same reason as above) OL is perpendicular to AB. So, OL bisects AB (same reason as above) Also, OL=OM=ON ... (i) To prove :- ∆ABC is an equilateral triangle. Proof :- From equation (i), AB=BC=CA (Chords equidistant from the centre of a circle are equal) Therefore, ∆ABC is an equilateral triangle. _________________________ Hope it helps you!

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