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In given fig o is centre …

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In given fig o is centre of circle.om is perpendicular BC,ol perpendicular ab ,on perpendicular AC,Om=on=ok.is triangle ABC equilateral triangle.give reason.chapter circle grade 9
  • 1 answers

Tanishq Pandya 3 years, 9 months ago

Given :- O is the centre of a circle. OM is perpendicular to BC. So, OM bisects BC (the perpendicular from the centre of a circle to a chord bisects the chord) ON is perpendicular to AC. So, ON bisects AC (same reason as above) OL is perpendicular to AB. So, OL bisects AB (same reason as above) Also, OL=OM=ON ... (i) To prove :- ∆ABC is an equilateral triangle. Proof :- From equation (i), AB=BC=CA (Chords equidistant from the centre of a circle are equal) Therefore, ∆ABC is an equilateral triangle. _________________________ Hope it helps you!
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