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Tan(A+B)=√3, tan (A-B)=1/√3,B to A,B ka …

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Tan(A+B)=√3, tan (A-B)=1/√3,<A+B<_90°<A>B to A,B ka man

Posted by Pinkal Kushwaha 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kiran Kumari 4 years, 8 months ago

Tan (A +B)=root 3=(A+B)=60 (1) TAN (A_B)=1/ROOT 3=(A_B)=30 (2) solving 1 and 2 we get 2a=90 A=45degree. Put the value of a in eq (1) 45+b=60 B=15degree

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Aachal Satwan 4 years, 8 months ago

Tan( A+B ) = √3. A+B = 60⁰ - (i) (∵tan 60⁰= √3) tan (A-B)=1/√3. A-B = 30⁰ -(ii) (∵tan 30⁰ = 1/√3) Add equation (i) and (ii) (A+B=60⁰) + ( A-B = 30⁰) 2A = 90⁰ A = 90⁰/2 A = 45⁰ Put A = 45⁰ in equation (i) A + B = 60⁰ 45⁰ + B = 60⁰ B = 60⁰ - 45⁰ B = 15⁰

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If 1/2 is a root of equation x^2+kx- 5/4 =0 , then what is the value of k

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CBSE > Class 10 > Mathematics