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In the figure, Quadrilateral ABCD is …

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In the figure, Quadrilateral ABCD is circumscribing a circle with centre O and AD⊥ AB. If the radius of incircle is 10 cm, then the value of x is

    • Posted by C Akhilesh 4 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 4 years, 3 months ago

    Let O be the mid point,

    As = Ap ( tangent to the given circle)

    and since L SAp is 90°

    As = OP = Ap = 10cm ( radius)

    Now, Let t be the point where Ap meets Cq

    and we know that Cq = PR = 27 (tangent)

    and Ct = 38 ( given in the fig)

    » Cq + qt = 38

    » 27cm + qt = 38cm

    » qt = 38cm-27cm = 11cm

    and now tp = tq ( tangent)

    tp = 11cm

    So to find x , i.e Apt

    we have Apt = Ap + pt

    = 10cm + 11cm = 21 cm

    0Thank You

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