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A vertical pole of length 6 …

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A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time; a tower casts a shadow 28m. Find the height of the tower

Posted by C Akhilesh 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Saniya Khanam 4 years, 8 months ago

Height of pole=AB=6 m Length of shadow of pole =BC=4 m Length of shadow of tower=EF=28 m In △ABC and △DEF ∠B=∠E=90∘ both 90∘ as both are vertical to ground ∠C=∠F (same elevation in both the cases as both shadows are cast at the same time) ∴△ABC∼△DEF by AA similarity criterion We know that if two triangles are similar, ratio of their sides are in proportion So,DEAB=EFBC ⇒DE6=284 ⇒DE=6×7=42 m Hence the height of the tower is 42 m I hope it will help you??

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CBSE > Class 10 > Mathematics