An object is placed 15cm from …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Surya Kumar 1 year, 5 months ago
- 1 answers
Posted by Tushar Sharma 1 year, 5 months ago
- 2 answers
Posted by Pandey Ji 6 months, 1 week ago
- 0 answers
Posted by Harshal Patil 10 months, 3 weeks ago
- 0 answers
Posted by Harshita Tondey 1 year, 5 months ago
- 3 answers
Posted by Aadarsh Tripathi 1 year, 5 months ago
- 2 answers
Posted by Rani Alan 1 year, 5 months ago
- 1 answers
Posted by Ansh Preet 10 months, 3 weeks ago
- 1 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 4 years, 6 months ago
radius of curvature = 90 cm
focal length = r/2 = +45 cm(since it is on the direction on the incident light)
object distance, u = - 15 cm (since it is on the opposite direction of the incident light)
we have to find v= ?
using mirror formula we get ,
1/v + 1/u = 1/f
so 1/ v = 1/f - 1/u
1/v = 1/ 45 - (1/-15) = 1/45 + 1/15 = 4/45
so v =45 / 4 cm
therefore image distance = 45 / 4 cm (positive sice it is in the direction of incident light)
0Thank You