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Find the 10 th term of the AP whose sum of n term is given by 2n^2 +3n

Posted by @/<$#!T Just Own 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Anisha ✌️ .. 4 years, 8 months ago

ANSWER S n =2n 2 +3n We know that nth term of AP is given by a n =S n −S n−1 ⟹a n =2n 2 +3n−2(n−1) 2 −3(n−1) ⟹a n =4n+1 Tenth term=a 10 =4×10+1 ⟹a 10 =41

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Shubham Chaudhary 4 years, 8 months ago

A=S1= 2×1^2+3×1=5 A2 = S2-S1 =( 2×2^2+3×2)-5 =14-5=9 ..........d=a2 - a1 = 9-5=4 a10= a + (n-1)d ........5+(10-1)×4 .........5+9×4=5+36=41 A10 =41

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Secret ??? 4 years, 8 months ago

Sn=2n²+3n, we know An=Sn-Sn-1(n is at foot and - 1 is from n)....... A10 =S10 - S9........ A10 =2×10²+3×10 - 2×9-3×9........... An=200+30-18-27........ An=185

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