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AB is a chord of a …

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AB is a chord of a circle with centre O and OM ⏊ AB. If OM = 5cm and AB = 8cm, find radius of the circle.

    • Posted by Bubbly Cs 3 years, 9 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Sahil Vinod Darekar 3 years, 9 months ago

    As AB is chord of length 8 cm we can find the radius of circle by using Pythagoras theorem. Therefore 5²=4²+ OP² 25-16=OP² 9=OP² OP=√9 OP=3 Proof 3²= 5²* 2AB | 25-9= 2AB 16=2AB AB =16/2 AB=8cm

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