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An AP consists of 50terms of …

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An AP consists of 50terms of which 3rd term is 12 and the last term is 106. Find the 29th term.

    • Posted by Susmita Muduli 4 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Yogita Ingle 4 years, 8 months ago

    Let a , d are first term and common

    difference of an A.P

    nth term = Last term = a + ( n - 1 )d
    an = a + ( n - 1 )d
    Now ,
    It is given that ,
    Third term = 12
    a + 2d = 12 ------( 1 )
    Last term = 106
    a + 49d = 106 ---( 2 )
    Subtract ( 1 ) from ( 2 ) , we get
    47d = 94
    d = 2
    Substitute d value in equation ( 1 ) ,
    We get
    a + 2 × 2 = 12
    a = 12 - 4
    a = 8
    29th term = a + 28d
    a29 = 8 + 28 × 2
    = 8 + 56
    = 64

    0Thank You

    Secret ??? 4 years, 8 months ago

    n=50 a+2d=12 - - - - 1 a49d106 - - - - - 2 by 2-1 we get, a+47d-a-2d= 106-12 47d=94 D=94/47 d=2 then a=8 a+(n-1)d=nth term 8+28×2=64

    0Thank You

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