Prove the Gauss law?

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Meghna Thapar 5 years ago
Gauss’s Theorem Statement:
According to Gauss’s theorem the net-outward normal electric flux through any closed surface of any shape is equivalent to 1/ε0 times the total amount of charge contained within that surface.
Proof of Gauss’s Theorem Statement:
Let the charge be = q
Let us construct the Gaussian sphere of radius = r
Now, Consider , A surface or area ds having having ds (vector)
Normal having the flux at ds:
Flux at ds:
d e = E (vector) d s (vector) cos θ
But , θ = 0
Therefore, Total flux:
C = f d Φ
E 4 π r2
Therefore,
σ = 1 / 4πɛo q / r2 × 4π r2
σ = q / ɛo
1Thank You