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X-1=8(y-1),x=y^2 solve for value of x …

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X-1=8(y-1),x=y^2 solve for value of x and y
  • 3 answers

Kiran Kumari 4 years, 8 months ago

Then x=y^2 X=(1)^2 X=1

Kiran Kumari 4 years, 8 months ago

X_1=8y_8 (1) ,x=y^2 Put the value of x^2 in eq (1) Y^2_1=8y_8 Y^2_8y+7=0 Y^2_7y_y+7=0 Y (y_7) _1 (y_7)=0 (Y_7) (y_1)=0 Y=7 ,y=1

Aachal Satwan 4 years, 8 months ago

x - 1 = 8(y - 1) y^2 - 1 = 8y - 8 (∵x=y^2) y^2 - 8y -1 +8 = 0 y^2 - 8y +7 = 0 y^2 - y -7y + 7 = 0 y (y-1) -7(y-1) = 0 (y -7) (y-1) = 0 ∴ either (y-7) =0 OR (y-1) = 0 ∴ y = 7 OR y= 1 i) If y= 7 , then x = y^2 = (7)^2 = 49 ii) If y = 1, then x = y^2 = (1)^2 = 1
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