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Q-11. ABC is a triangle in …

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Q-11. ABC is a triangle in which altitudes BE and CF to side AC and AB respectively. Show that ∆ABE = ∆ACF.
  • 2 answers

Yogita Ingle 3 years, 9 months ago

In ΔABE and ΔACF, 

∠BAE=∠CAF  (Common angle) 

∠AEB=∠AFC ....(∵BE⊥AC and CF⊥AB) 

BE=CF (Given that altitudes are equal)

By AAS criterion of congruence, 

ΔABE≅ΔACF

Hence, 

AB=AC (by CPCT)

Harsh Grover 3 years, 9 months ago

Angle A common angle E and angle F=90 AC =AB
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