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Q-11. ABC is a triangle in …

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Q-11. ABC is a triangle in which altitudes BE and CF to side AC and AB respectively. Show that ∆ABE = ∆ACF.

Posted by Arun Kushwah 5 years ago

CBSE > Class 09 > Mathematics

2 answers

Yogita Ingle 5 years ago

In ΔABE and ΔACF,

∠BAE=∠CAF (Common angle)

∠AEB=∠AFC ....(∵BE⊥AC and CF⊥AB)

BE=CF (Given that altitudes are equal)

By AAS criterion of congruence,

ΔABE≅ΔACF

Hence,

AB=AC (by CPCT)

1Thank You

Harsh Grover 5 years ago

Angle A common angle E and angle F=90 AC =AB

1Thank You

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