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Q-9. AB is a line segment …

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Q-9. AB is a line segment and line I is its perpendicular bisector. If a point P line on I . Show that P is equidistant from A and B.

Posted by Arun Kushwah 4 years, 11 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 11 months ago

since , AB is a line segment,
L is drawn perpendicular to AB,
A point 'p' lies on line L.
( as shown in the diagram in the attachment )
To prove : P is equidistant from A and B.
Prove :- In ∆AOP and ∆BOP ,
OP = OP ( common side )
POA = POB
AO = OB
∆AOP ∆BOP (By S.A.S.)
=> AP = BP ( By C.P.C.T. )
Hence , "P" is equidistant from A and B .

1Thank You

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CBSE > Class 09 > Mathematics