Q-9. AB is a line segment …
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Yogita Ingle 3 years, 9 months ago
since , AB is a line segment,
POA = 
POB
∆AOP 
∆BOP (By S.A.S.)
L is drawn perpendicular to AB,
A point 'p' lies on line L.
( as shown in the diagram in the attachment )
To prove : P is equidistant from A and B.
Prove :- In ∆AOP and ∆BOP ,
OP = OP ( common side )
AO = OB
=> AP = BP ( By C.P.C.T. )
Hence , "P" is equidistant from A and B .
1Thank You