Evaluate 1. (102)3 2. 140×96 3. …
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Posted by Nisha Murali 3 years, 9 months ago
- 3 answers
Abhay Singh 3 years, 9 months ago
Yogita Ingle 3 years, 9 months ago
Let us rewrite (102)3 as (100+2)3
Now using the identity (a+b)3=a3+b3+3ab(a+b), we get
(100+2)3=1003+23+[(3×100×2)(100+2)]
=1000000+8+(600×102)
=1000000+8+61200
=1061208
Hence, (102)3=1061208
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Nisha Murali 3 years, 9 months ago
2Thank You