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Evaluate 1. (102)3 2. 140×96 3. …

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Evaluate 1. (102)3 2. 140×96 3. (X+4) (x+10)

Posted by Nisha Murali 5 years ago

CBSE > Class 09 > Mathematics

3 answers

Nisha Murali 5 years ago

Thanks

2Thank You

Abhay Singh 5 years ago

Question 1. 102x3=306 2. 140x96=13440 3. (x+4)(x+10) =x+x of 4+10 = 2x of 14 = 28x answer.

3Thank You

Yogita Ingle 5 years ago

Let us rewrite (102)3 as (100+2)³

Now using the identity (a+b)³=a³+b³+3ab(a+b), we get

(100+2)³=100³+2³+[(3×100×2)(100+2)]

=1000000+8+(600×102)

=1000000+8+61200

=1061208

Hence, (102)³=1061208

2Thank You

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