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Q-5. In ∆PQR if /R >/Q …

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Q-5. In ∆PQR if /R >/Q then (A). QR>PR (B). PQ>PR (C). PQ>PR (D). QR>PR

Posted by Arun Kushwah 5 years ago

Given: In ΔPQR,

∠R >∠Q

⇒ PQ > PR (side opposite to greater angle is greater)

Hence, B is correct.

PR>PQ

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