Find the co-ordinate of center of …
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Yogita Ingle 4 years, 8 months ago
Let O (x, y) is the point of the circle
if three given points A (3,-7) B (3,3) and C (6,-6)
we know distance between circumference and center is always same. i.e radius .
now,
{tex}OA^2=OB^2=OC^2{/tex}
{tex}OA^2=OB^2{/tex}
{tex}=>(x-3)^2+(y+7)^2=(x-3)^2+(y-3)^2{/tex}
{tex}=>(x-3)^2-(x-3)^2=(y-3)^2-(y+7)^2{/tex}
{tex} => 0=(2y+4)(3){/tex}
{tex}=> y= -2{/tex}
now again ,
{tex}OB^2=OC^2{/tex}
{tex}(x-3)^2+(y-3)^2=(x-6)^2+(y+6)^2{/tex}
put y=-2
{tex}=>(x-3)^2+(-2-3)^2=(x-6)^2+(-2+6)^2{/tex}
{tex}=>(x-3)^2-(x-6)^2=16-25{/tex}
{tex}=>(2x-9)(3)=-9{/tex}
{tex}=> 2x= -3+9=6{/tex}
=> x=3
hence center co-ordinate is (3,-2)
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