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Find the distance of the point (-3,-4) from the x-axis ( in units)

Posted by Anushka ................. 5 years ago

CBSE > Class 10 > Mathematics

5 answers

Kunwar Dev Singh 4 years, 11 months ago

4 unit

0Thank You

Yogita Ingle 5 years ago

When we are asked to calculate the distance between a point and any of the axes, we calculate the perpendicular distance between them.

Therefore, the point (-3,-4) is 3 units away from the y-axis and 4 units from the x-axis. This is because in case of either axes the co-ordinate of the other axis is zero.

Therefore the distance between the point P(-3,-4) and x-axis is 4 units.

1Thank You

Divanshu Rawat 5 years ago

For x axis our point x2=-3 & y2=0 D=√[-3-(-3)]^2. + [0-(-4)]^2 =√(0)^2. + (4)^2 =√16 D=4 unit

0Thank You

Ansh Sharma 5 years ago

For x axis our point x2=-3 & y2=0 D=√[-3-(-3)]^2. + [0-(-4)]^2 =√(0)^2. + (4)^2 =√16 D=4 unit

0Thank You

Ishan Kumar 5 years ago

1Thank You

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