No products in the cart.

Find the distance of the point …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Find the distance of the point (-3,-4) from the x-axis ( in units)
  • 5 answers

Kunwar Dev Singh 4 years, 8 months ago

4 unit

Yogita Ingle 4 years, 8 months ago

When we are asked to calculate the distance between a point and any of the axes, we calculate the perpendicular distance between them.

Therefore, the point (-3,-4) is 3 units away from the y-axis and 4 units from the x-axis. This is because in case of either axes the co-ordinate of the other axis is zero.

Therefore the distance between the point P(-3,-4) and x-axis is 4 units.

Divanshu Rawat 4 years, 8 months ago

For x axis our point x2=-3 & y2=0 D=√[-3-(-3)]^2. + [0-(-4)]^2 =√(0)^2. + (4)^2 =√16 D=4 unit

Ansh Sharma 4 years, 8 months ago

For x axis our point x2=-3 & y2=0 D=√[-3-(-3)]^2. + [0-(-4)]^2 =√(0)^2. + (4)^2 =√16 D=4 unit

Ishan Kumar 4 years, 8 months ago

4
http://mycbseguide.com/examin8/

Related Questions

X-y=5
  • 1 answers
Prove that root 8 is an irration number
  • 2 answers
Venu Gopal has twice
  • 0 answers
(A + B )²
  • 1 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App