If p=2-a prove that a²+6ap+ p⁸- …
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Posted by Muskan Garg 3 years, 9 months ago
- 2 answers
Gaurav Seth 3 years, 9 months ago
It is given that ,
p = 2 - a -------( 1 )
LHS = a³ + 6ap + p³ - 8
= a³ + 6a( 2 - a ) + ( 2-a )³ - 8 [ from(1)]
= a³ +12a-6a²+2³-3×2²a+3×2a²-a³-8
= a³ + 12a - 6a² + 8 - 12a + 6a²- a³ - 8
= 0
= RHS
Hence proved.
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Dinesh G 3 years, 9 months ago
1Thank You