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PQ is a tangent at point …

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PQ is a tangent at point C at circle with center o.if AB is a diameter and ACB-30 find PCA

    • Posted by Subash Gouda 4 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 4 years, 8 months ago

    In the given figure,

    In Δ ACO,
    OA=OC (Radii of the same circle)
    Therefore,
    ΔACO is an isosceles triangle.
    ∠CAB = 30° (Given)
    ∠CAO = ∠ACO = 30° (angles opposite to equal sides of an isosceles triangle are equal)
    ∠PCO = 90° …(radius is drawn at the point of
    contact is perpendicular to the tangent)
    Now ∠PCA = ∠PCO – ∠CAO
    Therefore,
    ∠PCA = 90° – 30° = 60°

    0Thank You

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