Costruct a triangle ABC, in which …
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Posted by Swatantra Yadav 3 years, 9 months ago
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Yogita Ingle 3 years, 9 months ago
Steps of Construction:
1.Draw a line segment PQ = 11 cm.( = AB + BC + CA).
2.At P construct an angle of 60° and at Q, an angle of 45°.
3.Bisect these angles. Let the bisectors of these angles intersect at a point A.
4.Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.
5.Join AB and AC (see Fig. 11.9). Then, ABC is the required triangle.
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