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a3+b3+c3-3abc=?

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a3+b3+c3-3abc=?
  • 2 answers

Kripa Daga 3 years, 9 months ago

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)

Shalini Kumari 3 years, 9 months ago

Prove a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac) It is a special identity of polynomial of class 9.
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