The angle subtended by the diameter …
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Posted by Neshok Ls 3 years, 9 months ago
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Gaurav Seth 3 years, 9 months ago
The angle subtended by the diameter of a semicircle is 90o
To prove : ∠APB=90o
∵ We know angle subtended by an arc at centre is double the angle subtended at any point or circumference.
⇒ Angle subtended by arc AB at O= Double the angle subtended at P
⇒∠AOB=2∠APB
∵AOB is a straight line.
⇒∠AOB=1800
⇒2∠APB=180o
⇒∠APB=90o
∴ Angle subtended by arc AB or semi circle is 90o
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