Show that there exists no rational …
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Gaurav Seth 4 years, 8 months ago
Given,
Prove that there is no rational number whose square is
Let's assume that
, where
and
and
are co-prime.
Then we have,
So,
⇒
This implies that
is even.
Then,
So,
⇒
⇒
Thus,
⇒
⇒
Then,
∴%3D(%5Cfrac%7B5q%7D%7Bp%7D))
which contradicts
and
being co-prime.
Therefore,
is irrational.
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