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There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. Total number of sections thus formed is?

Posted by Charvi Sangwan 4 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 4 years, 6 months ago

The size of each section is to be selected in such a way, It divides both 576 and 488 exactly.

So you have to find HCF of 576 and 448 girls.

576 = 2 x 2 x 2 x 2 x 2 x 2x 3 x 3
448 = 2 x 2 x 2 x 2 x 2 x 2 x 7
Highest Common Factors = 2 x 2 x 2 x 2 x 2 x 2 = 64

(The Highest Common Factor (HCF) is the largest positive integer that divides all the given numbers. Hence the HCF is the biggest size for forming groups.)

Hence, number of sections required;
(576 ÷ 64) + (448 ÷ 64)
= 9 + 7 = 16.

Therefore, Total number of sections thus formed are 16.

0Thank You

Sajal Samveg 4 years, 6 months ago

Total number of sections must be 16.

0Thank You

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