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if d=HCF (48,72) find the value …

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if d=HCF (48,72) find the value of d is

Posted by Honey Tiwari 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 4 years, 8 months ago

If d is the hcf of 48 and 72 so the value of d will be the hcf of later
factor of 48 is
2,3,4,6,8,12,24 and 48
factor of 72 is
2,3,4,6,8,9,12,24,36 and 72
so the hcf is 24 and d= 24
or
d = HCF ( 48, 72 )

48 = 2 * 2 * 2 * 2 * 3

72 = 2 * 2 * 2 *3 * 3

so HCF = 2 * 2 * 2 * 3

➡ 24

Answer :- d = HCF ( 48, 72 ) = 24

1Thank You

ANSWER

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