Evaluate (103)2
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Pratham Chourasiya 3 years, 9 months ago
- 2 answers
Yogita Ingle 3 years, 9 months ago
{tex}(100+3)^2{/tex}
Using identity {tex}(a+b) ^2 =a^2 +b^2 +2ab{/tex}
{tex}=(100)^2 +(3)^2 +2×100×3{/tex}
= 10000+9+600
=10609
Related Questions
Posted by Savitha Savitha 2 months, 3 weeks ago
- 0 answers
Posted by Gnani Yogi 2 months, 2 weeks ago
- 0 answers
Posted by Akhilesh Patidar 2 months, 3 weeks ago
- 0 answers
Posted by Alvin Thomas 2 months, 2 weeks ago
- 0 answers
Posted by Sheikh Alfaz 3 days, 8 hours ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Karan Joshi 3 years, 9 months ago
0Thank You