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Evaluate (103)2

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Evaluate (103)2

Posted by Pratham Chourasiya 4 years, 11 months ago

Karan Joshi 4 years, 11 months ago

(100+3) (a+b)2 (100)2 + (3)2 + 600 10000 + 9 +600 =10609 answer

Yogita Ingle 4 years, 11 months ago

{tex}(100+3)^2{/tex}
Using identity {tex}(a+b) ^2 =a^2 +b^2 +2ab{/tex}
{tex}=(100)^2 +(3)^2 +2×100×3{/tex}
= 10000+9+600
=10609

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