A semi circular sheet of metal …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sahil Vinod Darekar 3 years, 9 months ago
- 3 answers
Gaurav Seth 3 years, 9 months ago
Slant height of the conical cup, 'l' = radius of the semi-circular sheet, R = 14 cm
Let radius and height of the conical cup be 'r' and 'h' respectively.
Circumference of the base of the cone = Length of arc of the semi-circle
Or, 2πr = (1/2)2πR
Or, 2πr = (1/2)(2π)(14)
Or, r = 7 cm
Now, we know that l² = h² + r²
(14)² = (h)² + (7)²
h² = 196 - 49
h = √147
Height or depth of the conical cup = 12.124 cm
Now, capacity of the conical cup = 1/3πr²h
= 1/3*22/7*7*7*12.124
= 13069.672/21
Capacity of the conical cup = 622.365 cu cm
Related Questions
Posted by Alvin Thomas 2 months, 2 weeks ago
- 0 answers
Posted by Savitha Savitha 2 months, 3 weeks ago
- 0 answers
Posted by Sheikh Alfaz 3 days, 8 hours ago
- 0 answers
Posted by Akhilesh Patidar 2 months, 3 weeks ago
- 0 answers
Posted by Gnani Yogi 2 months, 2 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sahil Vinod Darekar 3 years, 9 months ago
1Thank You