Slant height of the conical cup, 'l' = radius of the semi-circular sheet, R = 14 cm
Let radius and height of the conical cup be 'r' and 'h' respectively.
Circumference of the base of the cone = Length of arc of the semi-circle
Or, 2πr = (1/2)2πR
Or, 2πr = (1/2)(2π)(14)
Or, r = 7 cm
Now, we know that l² = h² + r²
(14)² = (h)² + (7)²
h² = 196 - 49
h = √147
Height or depth of the conical cup = 12.124 cm
Now, capacity of the conical cup = 1/3πr²h
= 1/3*22/7*7*7*12.124
= 13069.672/21
Capacity of the conical cup = 622.365 cu cm

1Thank You

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