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the sum of first three terms of an ap is 48 . if the product of first and second terms exceeds 4 times the third term by 12. find the ap

    • Posted by Mehul Kedia 4 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 4 years, 8 months ago

    Let the three terms be a-d,a,a+d

    Sum=a-d+a+a+d=48

    Solving this, we get

    3a=48

    a=16

    a(a-d)-4(a+d)=12

    Keeping the value of a in above equation

    16(16-d)-4(16+d)=12

    Solving this, we get

    d=9

    Therefore terms are 7,16,25 (ans)

    or

    Let the first three terms of the AP be (a-d), a and (a+d). Then,

    Hence, the first three terms of the AP are 7, 16, and 25.

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