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Chapter 12… exercise 12.3, 7th sum …

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Chapter 12… exercise 12.3, 7th sum Why can't we take the area of sectors instead of quadrants and then subtract it from the area of the square? They have taken the area of 4 quadrants

    • Posted by Samruddhi Br 4 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Tabrez Alam 4 years, 8 months ago

    व्यापार अवरोधक से क्या अभिप्राय है ?

    0Thank You

    Gaurav Seth 4 years, 8 months ago

     In Fig. 12.25, ABCD is a square of side 14 cm. With centres A, B, C and D, four circles are drawn such that each circle touch externally two of the remaining three circles. Find the area of the shaded region.

    Solution:

    Side of square = 14 cm

    Four quadrants are included in the four sides of the square.

    ∴ Radius of the circles = 14/2 cm = 7 cm

    Area of the square ABCD = 142 = 196 cm2

    Area of the quadrant = (πR2)/4 cm2 = (22/7) ×72/4 cm2

    = 77/2 cm2

    Total area of the quadrant = 4×77/2 cm2 = 154cm2

    Area of the shaded region = Area of the square ABCD – Area of the quadrant

    = 196 cm2 – 154 cm2

    = 42 cm2

    0Thank You

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