Find the area of triangle whose …
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Yogita Ingle 4 years, 8 months ago
Let A(2,3), B(−1,0) and C(2,−4) are the vertices of △ABC
Area of triangle= 1/2 [x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Here (x1,y1)=(2,3)
(x2,y2)=(−1,0)
(x3,y3)=(2,−4)
= 1/2 [2(0+4)−1(−4−3)+2(3−0)]
= 1/2 [8+7+6]
= 21/2 sq.unit
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