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Find the area of triangle whose …

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Find the area of triangle whose vertices are : (1). (2,3), (-1,0), (2,-4)
  • 1 answers

Yogita Ingle 4 years, 8 months ago

Let A(2,3), B(−1,0) and C(2,−4) are the vertices of △ABC

Area of triangle= 1/2 ​[x1​(y2​−y3​)+x2​(y3​−y1​)+x3​(y1​−y2​)]

Here (x1​,y1​)=(2,3)

(x2​,y2​)=(−1,0)

(x3​,y3​)=(2,−4)

= 1/2 ​[2(0+4)−1(−4−3)+2(3−0)]

= 1/2 ​[8+7+6]

= 21/2 ​ sq.unit

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