A force of 100N acting on …
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Poulami Dasgupta 8 years, 4 months ago
Using newton's second law
F= ma
100= {tex}m(v—u)\over t{/tex}
100 = {tex}m( 20—0)\over 5{/tex}
500= 20m
{tex}500\over 20{/tex} = m
25kg = m
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