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Find the least number which when …

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Find the least number which when divided by 35 56 and 91 leaving the same remainder 7 in each case

    • Posted by Anshu Khola 4 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Yogita Ingle 4 years, 10 months ago

    The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)
    35=5×7
    56=23×7
    91=7×13
    LCM=23×5×7×13=3640
    The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

    1Thank You

    Lomror ? 4 years, 10 months ago

    Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91.  Prime factorization of 35, 56 and 91 is:  35 = 5 × 7 & 56 = 23 × 7 & 91 = 7 × 13  LCM =23 × 5 × 7 × 13 = 3640  Least number which can be divided by 35, 56 and 91 is 3640.  Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647.

    2Thank You

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