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state and prove Gauss law

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state and prove Gauss law
  • 2 answers

Kislay Harsh 4 years, 4 months ago

The total electric flux through a body is equivalent to 1/epsilon times the charge on it.

Yogita Ingle 4 years, 4 months ago

According to Gauss’s law, the total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The total electric flux through a closed surface is zero if no charge is enclosed by the surface.

  • Gauss’s law is true for any closed surface, no matter what its shape or size.
  • The term q on the right side of Gauss’s lawincludes the sum of all charges enclosed by the surface. The charges may be located anywhere inside the surface.
  • In the situation when the surface is so chosen that there are some charges inside and some outside, the electric field [whose flux appears on the left side of Eq. (1.31)] is due to all the charges, both inside and outside S. The term q on the right side of Gauss’s law, however, represents only the total charge inside S.
  • The surface that we choose for the application of Gauss’s law is called the Gaussian surface. The Gaussian surface can pass through a continuous charge distribution.
  • Gauss’s law is useful for the calculation of the electrostatic field for a symmetric system.
  • Gauss’s law is based on the inverse square dependence on distance contained in the Coulomb’s law. Any violation of Gauss’s law will indicate departure from the inverse square law.

 

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