in a survey of 25 students, …
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Gaurav Seth 4 years, 2 months ago
Total no. of student=25
Let n(M)=student who studying mathematics
n(C)=student who studying chemistry
n(P)=student who studying Physics
∴n(M)=15,n(P)=12,n(C)=11,n(M∩P)=9,n(M∩C)=5,n(P∩C)=4,n(M∩P∩C)=3
Number of student who studying mathematics and physic but not chemistry
⇒n(M∩P)−n(M∩P∩C)
⇒9−3=6
Number of student who studying chemistry and physic but not mathematics
⇒n(P∩C)−n(M∩P∩C)
⇒4−3=1
Number of student who studying mathematics and chemistry but not physics
⇒n(M∩C)−n(M∩P∩C)
⇒5−3=2
∴No.of student who had taken two of the three subjects=6+1+2=9
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