A rope 1cm in diameter breaks …
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Yogita Ingle 4 years, 2 months ago
it is based on Young's modulus concepts .
we know, Young's modulus = stress/strain
stress = F/A , strain = ∆L/L
so, Young's modulus, Y = FL/A∆L
so, F = YA∆L/L
hence, it is clear that tension in rope is directly proportional to area of cross section of rope.
area of cross section of rope , A = πd²/4
so,
we can write ,
so,
hence, maximum tension that may be given to a similar role of diameter 2cm is 2000N
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