A rope 1cm in diameter breaks …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Mohammed Javith 8 months, 4 weeks ago
- 0 answers
Posted by M D 8 months, 2 weeks ago
- 1 answers
Posted by Mansi Class 9Th 8 months, 3 weeks ago
- 0 answers
Posted by Nekita Baraily 8 months, 3 weeks ago
- 2 answers
Posted by Pankaj Tripathi 8 months, 3 weeks ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 4 years, 3 months ago
it is based on Young's modulus concepts .
we know, Young's modulus = stress/strain
stress = F/A , strain = ∆L/L
so, Young's modulus, Y = FL/A∆L
so, F = YA∆L/L
hence, it is clear that tension in rope is directly proportional to area of cross section of rope.
area of cross section of rope , A = πd²/4
so,
we can write ,
so,
hence, maximum tension that may be given to a similar role of diameter 2cm is 2000N
1Thank You