Derive an expression for potential energy …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Mahesh Rana 4 years, 9 months ago
- 1 answers
Related Questions
Posted by Khushbu Otti 1 year, 2 months ago
- 0 answers
Posted by Anterpreet Kaur 1 year, 3 months ago
- 0 answers
Posted by Aniket Mahajan 7 months, 2 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 4 years, 9 months ago
Considera dipole with charges +q and -q placed in a uniform eletric field as shown in figure.
In unifor electric field, dipole experiences a torque τ, which is given by
τ = p×E
where p is electric dipole moment. Torque τ will tend to rotate the dipole if p is not parallel to E.
Suppose an external torque τext is applied to neutalize this torque and rotates the dipole from an angle θo to θ1
at an infinitesimal angular speed and without angular acceleration. The amount of workdon by the external torque will be given by
W =
This work is stored as the potential energy of the system.
We can then assosciate potential energy U(θ) with an inclination θ of the dipole. Inorder to choose the
reference angular position where potential Energy is considered as zero, we select θo as π/2 as the reference angular position.
We can then write U(θ) = pE( cos(π/2) - cosθ) = -pE cosθ = -p·E
when θ = 0 , i.e., p is aligned in the direction of E, potential energy is minimum.
when θ = π , i.e., p is aligned in the oposite direction of E, potential energy is maximum
2Thank You