find the ratio in which the …
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Yogita Ingle 4 years, 8 months ago
Let the point be A(5,−6), B(−1,−4) and P(0,y)
Point P is on y−axis,hence its x co-ordinate is 0.So, it is of the form P(0,y)
Now, we have to find ratio.
Let the ratio be k:1
Hence m1=k,m2=1,x1=5,y1=−6,x2=−1,y2=−4,x=0,y=0
Using sections formula x= (m1x2+m2x1)/m1+m2
⇒0=−k+5/k+1
∴k=5
Again y=(m1y2+m2y1)/m1+m2
=−4k−6/ k+1 = (−20−6)/ 6 for k=5
=−13/3
Hence the coordiantes of point is P(0,−13/3)
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