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If cosA+cos3A+cos5A+cos7A÷sinA+sin3A+sin5A+sin7A =cot x, then x=?

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If cosA+cos3A+cos5A+cos7A÷sinA+sin3A+sin5A+sin7A =cot x, then x=?

    • Posted by Rishitha Rishitha 3 years, 10 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Ankit Raj 3 years, 10 months ago

    This is not in Class 9... SinA+sin3A+sin5A+sin7A÷ cosA+cos3+cos5A+cos7A=cot x (SinA+sin7A)+(sin3A+sin5A)÷(cosA+cos7A)+(cos3A+cos5A) = 2sin4A(cos3A+cosA)÷2cos4A(cos3A+cosA) = Sin4A÷cos4A =Cot4A=tanx ....so answer is x=4A

    0Thank You

    Rupali Sahu 3 years, 10 months ago

    SinA+sin3A+sin5A+sin7A÷ cosA+cos3+cos5A+cos7A=cot x (SinA+sin7A)+(sin3A+sin5A)÷(cosA+cos7A)+(cos3A+cos5A) = 2sin4A(cos3A+cosA)÷2cos4A(cos3A+cosA) = Sin4A÷cos4A =Cot4A=tanx ....so answer is x=4A

    0Thank You

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