Factorise 6kt^2 - 21 kt - …
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Posted by # G*Nius Parker 3 years, 10 months ago
- 1 answers
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Yogita Ingle 3 years, 10 months ago
6kt2 - 21kt -12k
taking out common 3k
3k(2t2 - 7t - 4)
= 3k(2t2 - 8t +t -4)
= 3k[ 2t(t - 4) +1(t-4)]
= 3k(t-4)(2t+1)
dimensions are 3k , t-4 , 2t+1
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