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A piece of wire 40 ohm …

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A piece of wire 40 ohm is drawn so its length twice its original value. Calculate the resistance of wire in new situation.
  • 1 answers

Tanisha Bharti 5 years ago

Length of first wire is L and second is 2L. Area crossecation of first wire A and second is A'. L×A=2L×A' A'=A/2 R=row ×L/A=40 ohm R'=row×2L/A'/2 4×row×L/A 4×40 ohm =160ohm answer
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