The focus of the parabola is …
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Yogita Ingle 4 years, 2 months ago
We have this equation:
x + y = 1
x + y = 1
y = - x + 1
The slope of the tangent here is -1
And the slope of the line perpendicular to the tangent is 1
The line will pass through the focus y = x + c which will pass through (1,1)
The equation for this would be: y = x
The point of intersection of x + y = 1 and x = y can be obtained by:
y + y = 1
2y = 1
y = 1/2
The vertex for this is : (1/2, 1/2)
The distance between the focus and vertex is √[2x(1/2)²] = √2/2
The equation of parabola would be (y -1/2)² = (2x√2) x (x-1/2) y² + 1/4 - y = 2√2*x - √2
= 4y² - 4y - 8 x √2 *x + 4*√2 + 1 = 0
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