Find the nature of the roots …

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Posted by Hemavardhini Madhu 4 years, 11 months ago
- 2 answers
Hemavardhini Madhu 4 years, 11 months ago
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Yogita Ingle 4 years, 11 months ago
(i) 2x2 – 3x + 5 = 0
Here, a = 2, b = -3, c = 5
b2 – 4ac = (-3)2 – 4(2) (5
= 9 – 40 = -31
b2 – 4ac = -31 < 0
It has no real roots.
(iii) 2x2 – 6x + 3 = 0
Here, a = 2, b = -6, c = 3
b2 – 4ac = (-6)2 – 4(2)(3) = 36 – 24 = 12
∴ b2 – 4ac = 12 > 0.
∴ It has two distinct roots. 2x2 – 6x + 3 = 0 Here, a = 2, b = -3, c = 3
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