Convert inclusive class interval 10-19, 20- …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Keshav Gupta 3 years, 10 months ago
- 3 answers
Gaurav Seth 3 years, 10 months ago
Since the frequency table is in inclusive form we will first convert it into exclusive form by adding h/2 to upper limit and subtracting h/2 to lower limit.
Now we have
Frequency(f1)
9.5-19.5
19.5-29.5
29.5-39.5
39.5-49.5
49.5-59.5
Yogita Ingle 3 years, 10 months ago
10−19,20−29,30−39,...
Here the class intervals are not continuous. To make them continuous take the mean of upper limit of first class and lower limit of second class.
Mean = (19+20)/2 = 19.5, which gives the upper limit of first class and lower limit of second class for the continuous class intervals.
Related Questions
Posted by Akhilesh Patidar 2 months, 3 weeks ago
- 0 answers
Posted by Savitha Savitha 2 months, 3 weeks ago
- 0 answers
Posted by Gnani Yogi 2 months, 2 weeks ago
- 0 answers
Posted by Sheikh Alfaz 3 days, 14 hours ago
- 0 answers
Posted by Alvin Thomas 2 months, 2 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 3 years, 10 months ago
Since the frequency table is in inclusive form we will first convert it into exclusive form by adding h/2 to upper limit and subtracting h/2 to lower limit.
Now we have
9.5-19.5
19.5-29.5
29.5-39.5
39.5-49.5
49.5-59.5
2Thank You