Find two consecutive positive intiger whose …
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Posted by Jhon Rathi 4 years, 8 months ago
- 2 answers
Gaurav Seth 4 years, 8 months ago
Let
first number = x
since this no are consecutive so
second number = x+1
now according to question
x (x+1) = 110
x² + x = 110
x² + x - 110 = 0
by using factorization method
x² + 11x - 10x -110 = 0
x(x+11) -10(x+10) = 0
(x+11) (x-10) = 0
∵ x = -11 and x = 10
The two numbers would be 10 and 11.
10 x 11 = 110
10 + 11 = 21
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Karan Jaiswal 4 years, 8 months ago
0Thank You