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A magnetic moment of 1.73 BM …

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A magnetic moment of 1.73 BM will be shown by which of the following: A. TiCl4 B. [CoCl6] 4- C. [Cu(NH3)4] 2+ D. [Ni(CN)4] 2

    • Posted by Vicky Wani 3 years, 11 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Yogita Ingle 3 years, 11 months ago

    Electronic configuration of Cu2+ ion in [Cu(NH3​)4​]2+.
    Cu2+ ion =[Ar]3d94s0.
    ∴Cu2+ ion has one unpaired electron.
    Magnetic moment of [Cu(NH3​)4​]2+(μ)=n(n+2)​BM
    where, n=no. of unpaired electrons
    μ = √1(1+2) ​= √3 ​= 1.73BM
    Whereas Ni2+ in [Ni(CN)4​]2−,Ti4+ in TiCl4​ and Co2+ ion [COCl6​]4− has 2,0 and 3 unpaired electrons respectively.

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