A compound microscope has an objective …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Maria Anna Alwin 4 years, 9 months ago
- 3 answers
Gaurav Seth 4 years, 9 months ago
◆ Answer -
L = 7.5 cm
● Explanation -
# Given -
fo = +1.25 cm
fe = +5 cm
uo = -2.5 cm
ve = ∞
# Solution -
Applying lens formula for objective,
1/fo = 1/vo - 1/uo
1/1.25 = 1/vo - 1/-2.5
1/vo = 1/25 - 1/2.5
1/vo = 1/2.5
vo = 2.5 cm
Applying lens formula for eyepiece,
1/fe = 1/ve - 1/ue
1/5 = 1/∞ - 1/ue
1/5 = 0 - 1/ue
ue = -5 cm
Distance between the objective and eyepiece is -
L = |vo| + |ue|
L = |2.5| + |-5|
L = 2.5 + 5
L = 7.5 cm
Hence, distance between the objective and eyepiece is 7.5 cm.
Related Questions
Posted by Anterpreet Kaur 1 year, 3 months ago
- 0 answers
Posted by Aniket Mahajan 7 months, 1 week ago
- 0 answers
Posted by Khushbu Otti 1 year, 2 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Harsh Mishra 4 years, 9 months ago
2Thank You